If one zero of the polynomial 7x²+13x-3k is the reciprocal of the other, then find the value of k.
Answers
Answered by
1
Answer:
-7/3
Step-by-step explanation:
let one zero be x so other will be 1/x
we know, product of roots=c/a in general form of ax²+bx+c
here product of roots = x . 1 /x = 1 = c/a
comparing with given c=-3k a=7
=>-3k/7=1
=>k=-7/3
Answered by
1
Step-by-step explanation:
Let one zero will be a
then another zero be= 1/a
we know product of root will become
(a×1/a)= -3k
1 = -3k
therefore
k= -1/3
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