Question

if one zero of the polynomial 9x²-5x-(2k+3) is reciprocal of the other,find the value of k​

Answer 1

Answer:

l don't know this answer

Answer 2

$\huge\mathcal{\fcolorbox{cyan}{black}{\pink{ANSWER}}}$

Here one root is :

$\alpha$

so other root will be :

$\frac{1}{ \alpha }$

Now the polynomial is :

$9 {x}^{2} - 5x - (2k + 3) \\ \\ so \\ \alpha \times \frac{1}{ \alpha } = \frac{ - (2k + 3)}{9} \\ \implies \: \cancel \alpha \times \frac{1}{ \cancel \alpha } = - \frac{(2k + 3)}{9} \\ \implies \: - 2k - 3 = 9 \\ \implies \: 2k = - 12 \\ \therefore \: k = - 6$