if one zero of the polynomial (a^2 +9) x^2 +13x +6a is a reciprocal of the other. find these values of a
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Let one zero is P
then , other zero will be 1/P
now, product of zeros = constant/coefficient of x²
P × 1/P = 6a/(a² + 9)
1 = 6a/(a² + 9)
a² + 9 = 6a
a² -6a + 9 = 0
(a - 3)² = 0
a = 3
hence , a = 3
then , other zero will be 1/P
now, product of zeros = constant/coefficient of x²
P × 1/P = 6a/(a² + 9)
1 = 6a/(a² + 9)
a² + 9 = 6a
a² -6a + 9 = 0
(a - 3)² = 0
a = 3
hence , a = 3
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