if one zero of the polynomial( a^2+9)x^2+13x+6a is reciprocal to the other fin the value of a
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hey mate here is your answer
Step-by-step explanation:
If one of the zero is reciprocal of the other,
let one zero be α
other zero will be 1/α
Product of roots = c/a
⇒ α × 1/α = 6a/(a²+9)
⇒ 1 = 6a/(a²+9)
⇒ a² + 9 = 6a
⇒ a² - 6a + 9 = 0
⇒ a² - 3a - 3a + 9= 0
⇒ a(a-3) -3(a-3) = 0
⇒ (a-3)(a-3) = 0
⇒ (a-3)²= 0
⇒ a = 3
Value of a is 3.
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