if one zero of the polynomial (a^2+9)x^2+13x+6a is reciprocal of the other . find the value of a?
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6a/(a^2+9) =1
a^2-6a+9=0
(a-3)^2=0
a=0
a^2-6a+9=0
(a-3)^2=0
a=0
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