Question

if one zero of the polynomial (a^2-9)x2+13x+6a is reciprocal of the other then find the value of a​

Answer 1

Answer:

3, 3 ( equal zeros)

Step-by-step explanation:

see by applying product of zeros both zeros ger camy remains 1 = 6a÷ (a2-9) so by transforming as quadratic polynomial as equation by making =0 then we get as a2- 6a-9=0 then by applying ( a+b)2 formula ( a-3)2=0 then a= 3,3 ok

Answer 2

Step-by-step explanation:

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