if one zero of the polynomial (a^+25)x^2+13x-10a is reciprocal of the other find the value of a.
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hey frnd here is your answer
Step-by-step explanation:
your polynomial is (a²+25)x²+13x-10a
u have given that one is reciprocal of other
It is only possible when coefficient of x²= Constant term i.e a=c
so a²+25= -10a
a²+10a+25
this is equal to (a+5)²
so from here a=.-5
so frnd your final answer is a= -5
I hope you get your answer
thnx for asking
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