If one zero of the polynomial (a+5)xsquare + 13x +6a is reciprocal of the other find value of a
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Answer:
Just see the image.
Hope it helps.
For your information sum of roots = coefficient of x/coefficient of x^2 and
Product of roots= constant/coefficient of x^2
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Given:- If one zero is reciprocal of the other i.e.α=1/β
To find: Value of a
Sol.:- αβ = c/a
1/β*β=6a/a+5
1 = 6a/a+5
a+5=6a
5 = 5a
a=1
Therefore, Value of a=1.
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