if one zero of the polynomial (a square +9)x square +13x+6a is reciprocal of the other find a
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the value of a is 3 I hope it is helpful
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Answer:
3
Step-by-step explanation:
Let one zero = a
Other zero = 1/a (according to question)
Product of zeros = a* 1/a =1
C/A = 1
6/(a^2+9) = 1
6= a^2+9
a^2+9-6 = 0
a^2+3^2-2(a)(3) (by Identity)
a^2-6a+9
a^2-3a-3a+9 (by middle term splitting)
(a-3)(a-3)
a=3
Hope it helps
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