if one zero of the polynomial (a square+9)xsquare +13x+6a is reciprocal of the other then find the value of a
Answers
Answered by
2
hi friend, here is your answer for this question.
hope it helps and best of luck for math.
hope it helps and best of luck for math.
Attachments:
Answered by
1
Let the zeroes of the polynomial be α and 1/α
Product of zeroes=(coefficient of constant term)/(coefficient of x²)
α×(1/α)=6a/a²+9
⇒1=6a/a²+9
⇒a²+9=6a
⇒a²+9-6a=0
⇒a²-6a+9=0
⇒a²-3a-3a+9=0
⇒a(a-3)-3(a-3)=0
⇒(a-3)(a-3)=0
⇒(a-3)²=0
⇒a-3=0
⇒a=3
∴a=3
Product of zeroes=(coefficient of constant term)/(coefficient of x²)
α×(1/α)=6a/a²+9
⇒1=6a/a²+9
⇒a²+9=6a
⇒a²+9-6a=0
⇒a²-6a+9=0
⇒a²-3a-3a+9=0
⇒a(a-3)-3(a-3)=0
⇒(a-3)(a-3)=0
⇒(a-3)²=0
⇒a-3=0
⇒a=3
∴a=3
Similar questions