If one zero of the polynomial ( a2 + 25)xn2 + 36x +10a is the reciprocal of the other, find the value of a
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If one zero of the polynomial ( a2 + 25)xn2 + 36x +10a is the reciprocal of the other,
product of zeroes=1
10a/(a^2+25)=1
a^2+25=10a
a^2-10a+25=0
(a-5)^2=0
a=5
product of zeroes=1
10a/(a^2+25)=1
a^2+25=10a
a^2-10a+25=0
(a-5)^2=0
a=5
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