Question

If one zero of the polynomial ( a2

+ 9 ) x2

+ 13 x + 6a is the reciprocal of the other , find the value

of a .

Answer 1

Answer:

Step-by-step explanation:product of zeroes=c/a

a*1/a=6a/a2+9

1=6a/a2+9

a2+9=6a

a2-6a+9=0

a2-3a-3a+9=0

a(a-3)-3(a-3)=0

a=3