Question

If one zero of the polynomial (a²+9)x²+13x+60 is reciprocal the other, then find the value of a.​

Answer 1

Answer:

a = √51

Step-by-step explanation:

f(x)= (a^2+9)x^2+13x+60

Let one zero be y

Then , other zero will be 1/y

Hence, product of zeroes = c/a

=> y×1/y = 60/(a^2+9)

=> (a^2+9)=60

=> a^2 = 51

=> a = √51