Question

If one zero of the polynomial (a2 – 9) x2 + 13x + 6a is reciprocal of the other, find the value of ‘a’.

Answer 1

Answer:

3

Step-by-step explanation:

It is given that one of the 0 is reciprocal of the other

Let one 0 be a

Then the other be 1/a

Product of roots = c/a

=》a×1/a=6a/(a^2+9)

=》1=6a/(a^2+9)

=》a^2+9=6a

=》a^2-6a+9=0

=》a^2-3a-3a+9=0

=》a(a-3)-3(a-3)=0

=》(a-3)(a-3)=0

=》(a-3)^2=0

=》a=3.

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