Question

If one zero of the polynomial (a2 + 9)x2 + 13x
+ 6a is reciprocal of the other, find the value
of a.

​

Answer 1

Answer:

We know that equation ax

2

+bx+c=0

Then sum of roots =

a

−b

and product of roots=

a

c

Let the other zero be α

Therefore, the other zero is

α

1

Now, α× α1

= a2−96a

=>1= a 2−96a

=>a 2

+9−6a=0

=>a 2

−6a+9=0

=>a 2

−3a−3a+9=0

=>a(a−3)−3(a−3)=0

=>(a−3)(a−3)=0

=>a=3 and a=3

Answer 2

Answer:

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