Question

If one zero of the polynomial (a2

+ 9)x2

+ 13x + 6a is reciprocal to the other.

Find the value of ‘a’.

Answer 1

let one zero =a ,other zero =1/a
product of zeroes =13/a2+9
a×1/a =13/a2+9
1 =13/a2 +9
a2 +9 =13
a2 =13 -9
a2 =4
a=±2