Question

If one zero of the polynomial (a²+a)x+13x-6a is reciporcal of the other then a=?

Answer 1

here is your answer

suppose one zero be y.
other zero = 1/y

p(x)=(a²+a)x+13x-6a

product of zeroes=c/a

y×1/y=-6a/(a²+a)
a²+a =-6a
a²+7a =0
a(a+7)=0
a=-7

Hope it helps you ^_^

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