Math, asked by mohammedsohail0809, 11 months ago

if one zero of the polynomial (a2+a)x2 +13x +6x is reciprocal of the other, find the value of a

Answers

Answered by HEMANTHKUMAR007
2

Here,

P(x) = {(a^2+a)x^2 + 13x + 6}

Let us consider the two roots as {\huge{\frac{1}{a}}} and a.

Therefore ,

Product of roots = {\huge{\frac{1}{a}}} * a

Product of roots = 1

After this , see the attachment .

\underline{\mathfrak{\huge{Thank\: You}}}

Attachments:

mohammedsohail0809: it was 6a not 6 :(
HEMANTHKUMAR007: no it's 6 only
HEMANTHKUMAR007: not 6x
HEMANTHKUMAR007: I had already done this sum
mohammedsohail0809: i got the ans. a=0, 5
HEMANTHKUMAR007: no that wrong
HEMANTHKUMAR007: I had already done this sum
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