Question

If one zero of the polynomial (asquare + 9)xsquare + 13x +6a is a reciprocal of the other, find the value of a .

Answer 1

$here \: is \: your \: \\ \\ \\ \\ hope \: it \: help \: you$

Answer 2

let the one of the zero is p then another zero is 1/p
now product of zeroes = c/a
1/p ×p = 6a/a^2 +9
a^2 +9 = 6a from this find the value of a which is 3
now sum of zeroes = -b/a
1/p +p= -13/a^2 + 9
p^2 + 1 = -13p/ 9+9 ( by putting the value of a)

18p^2 + 18 =-13p now solve this quadratic eqn u get your ans