Math, asked by hetpatel2, 1 year ago

if one zero of the polynomial f(x)=4x(square)-8kx-9 is negative of other find the value of k

Answers

Answered by satyamkumar15

the value of k=13/8 if it's answer is wrong please please tell me

hetpatel2: canu show me that how u solveg

hetpatel2: solved

hetpatel2: plz

satyamkumar15: g(x)=o,x+1=o,x=-1. p(-1)=4*(-1) square-8k(-1)-9. p(-1)=-4+8k-9. -13+8k=o. 8k=13. k=13/8

Answered by Anonymous

Answer :-.---

→ k = 0 .

Step-by-step explanation :-

It is given that,

→ One zeros of the given polynomial is negative of the other .

Let one zero of the given polynomial be x .

Then, the other zero is -x .

•°• Sum of zeros = x + ( - x ) = 0 .

But, Sum of zeros = -( coefficient of x )/( coefficient of x² ) = - ( -8k )/4 .

==> 2k = 0 .

==> k = 0/2 .

•°• k = 0 .

Hence, it is solved.

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