if one zero of the polynomial f(x)=(k²+4)x²+13x+4k is the reciprocal of the other then k=
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let one zero be a then the other will new/a
clearly from the above step we can see that the product of the roots is so c/a=7
4k=k²+4
k²-4k+4=0
(k-2) (k-2)
hence=2
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