If one zero of the polynomial f(y) = (m2 + 4 )y2 + 13y + 4m is reciprocal of the other , then m is equal to
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1
Answer:
let one root be x then other root will be 1/x
f(y)=( m^2+4)y^2 + 13y+ 4m=0
product of the zeros = x(1/x)= 1
we know that in a quadratic equation of the form:
ax^2+bx+c=0
product of the roots or zeros = c/a
so in the equation given ,
product of the roots is 4m/(m^2+4)
4m/(m^2+4)=1
m^2 -4m+4=0
(m-2)^2=0
m=2
Answered by
0
Answer:
M=2
Step-by-step explanation:
Actually I think, full solution is not needed, kindly go and check it out.
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