Question

If one zero of the polynomial is 3X²-8 X + 2K+1 is seven times the other ,then the zeros are?

Answer 1

Answer:

3x²-8x+2k+1 a=3, b=-8 ,c=2k+1

suppose the zeroes of the equation are α and β . by the given condition α=7β

as we know, α+β=-b/a

7β+β=-(-8)/3

8β=8/3

β=8/3×1/8=1/3

αβ=c/a

7β×β=2k+1/3

7×1/3×1/3=2k+1/3

7/9=2k+1/3

21/9=2k+1

21/9-1=2k

12/9=2k

4/3=2k

4/6=k

2/3=k