Question

If one zero of the polynomial (k-1)x2+kx+1 is -3, then find the value of k.​

Answer 1

Answer:

(k-1)×2+Kx+1=0. (0=-3)

K-1×2+(-3K)+1.=0.

k-1×2-3k+1=0

2+1=-k-1-3k.

3=-2k-1.

3+1=2k.

4/2=k

2=k