Question

If one zero of the polynomial p(x) = 5x^2 + 13x + m is reciprocal of other, then find the
value of 'm'.​

Answer 1

Answer:

m=5 is the answer

Step-by-step explanation:

Hope its right

Answer 2

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Given :-

The polynomial p(x) = 5x²+ 13x + m have one zero reciprocal of the other.

To find :-

• The value of m

♤Formula used :- ♤

$\large\bold\green{Sum \: of \: zeroes = - \frac{b}{a} }$

$\large\bold\green{Product \: of \: zeroes = \frac{c}{a} }$

Solution:-

p(x) = 5x² + 13x + m

On comparing with ax² + bx + c

we get,

a = 5

b = 13

c = m

$Let \: the \: zeroes \: be \: \alpha \: and \: \frac{1}{ \alpha }$

$So, \: using \: Product \: of \: zeroes = \frac{c}{a} \\ \alpha \times \frac{1}{ \alpha } = \frac{m}{5} \\ 1 = \frac{m}{5} \\ = > m = 5$

$\huge \fcolorbox{black}{cyn}{♛Hope it helps U♛}$