If one zero of the polynomial p(x) = (a 2 + 9) x 2 + 45x +6a is reciporocal of the other find the value of a
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Let the zeroes be α and 1/α
product of zeroes = (a²+9)/6a= α×1/α = 1
⇒a²+9 = 6a
⇒a² -6a +9 =0
⇒(a-3)² = 0
⇒a = 3
product of zeroes = (a²+9)/6a= α×1/α = 1
⇒a²+9 = 6a
⇒a² -6a +9 =0
⇒(a-3)² = 0
⇒a = 3
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