Question

if one zero of the polynomial p(x)=axsquare-3(a-1)x-1 is 1 then find the value of a...

Answer 1

Given Quadratic Equation is f(x) = ax^2 - 3(a - 1) x - 1.

Given that 1 is the zero of the polynomial, then f(1) = 0.

Put x = 1 in f(x), we get

a(1)^3 - 3(a - 1)1 - 1 = 0

a - 3a + 3 - 1 = 0

-2a + 2 = 0

-2a = -2

a = 1.

Therefore the value of a = 1.

Hope this helps!

Answer 2

Given polynomial,
p(x) = ax²-3(a-1)x - 1

One zero of the polynomial is 1

Put x = 1,
p(1) = a(1)² - 3(a-1)(1) - 1 = 0
a(1) - 3a + 3 - 1 = 0
a - 3a + 2 = 0
-2a = -2
2a = 2
a = 2/2
a = 1

The value of a is 1