if one zero of the polynomial p(x) = x^2+5x+k is one more than the other, then find the value of k.
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Answered by
26
♠Answer♠
Here , As The Roots are consecutive , Difference of roots = 1 .
As we know , Difference of roots = √D/a
So , √( b² - 4ac ) = 1
B² -4ac = 1
b² = 1 + 4ac
25 = 4k + 1
k = 6
Which Is The Required Value .
#SupermanINFINITY
Here , As The Roots are consecutive , Difference of roots = 1 .
As we know , Difference of roots = √D/a
So , √( b² - 4ac ) = 1
B² -4ac = 1
b² = 1 + 4ac
25 = 4k + 1
k = 6
Which Is The Required Value .
#SupermanINFINITY
RaunakRaj:
b^2=1+4ac hoga thus answer is 6..
Answered by
49
Let the roots be a and a+1. Then,
a+a+1=(-5)
2a=(-6)
a=(-3)
and
a(a+1)=k
So,
(-3)(-2)=k
k=6
PLZ MARK IT AS BRAINLIEST..
a+a+1=(-5)
2a=(-6)
a=(-3)
and
a(a+1)=k
So,
(-3)(-2)=k
k=6
PLZ MARK IT AS BRAINLIEST..
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