if one zero of the polynomial p(x) = x^2+5x+k is one more than the other, then find the value of k.
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Answer:
let one of the zero be p and another be p + 1
(x-p)(x-p-1) =x^2-xp-x-px-p^2+p
=x^2-x(2p-1)-p^2+p
from this we can say that
5x = -x(2p-1)
by solving we get p = - 2
k = -p^2+p so answer is -6
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