Question

if one zero of the polynomial p(x)=x^2-6x+k is twice the other then find the value of k​

Answer 1

Answer:

8

Step-by-step explanation:

We know sum of roots of a quadratic equation =

$\frac{ - b}{a}$

$\frac{ - ( - 6)}{1} = x + 2x$

$6 = 3x$

$x = 2$

We know product of roots of a quadratic equation =

$\frac{k}{a}$

Thus,

$k = x \times 2x$

$k = 2 {x}^{2}$

$k = 2( {2}^{2} )$

$k = 8$