Math, asked by Jaggu2003, 11 months ago

If one zero of the polynomial px=ax2-3(a-1)x-1 is 1, then the value of a is

Answers

Answered by ajushujaltigerz
2

Answer:

a =1

Step-by-step explanation:

p(x)= ax^2 -3(a-1)x-1 =0

p(1)=a(1)^2 -3(a-1)1 -1 = 0

a -3a +3 -1 = 0

-2a +2 =0

-2a= -2

a = 1

Answered by LaraMohanty
0

Answer:

1/2

Step-by-step explanation:

As 1 is the zero of the given polynomial, it means that it satisfies the given polynomial. So put 1 is the polynomial

1 = a(1)²-3(a-1)(1)-1

     = a - 3a + 3 - 1

     = 2-2a

Taking 2a on the other side and bringing 1 to the opposite side, we get

2a = 2-1 = 1

⇒a = 1/2

HOPE THIS HELPS YOU

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