If one zero of the polynomial px=ax2-3(a-1)x-1 is 1, then the value of a is
Answers
Answered by
2
Answer:
a =1
Step-by-step explanation:
p(x)= ax^2 -3(a-1)x-1 =0
p(1)=a(1)^2 -3(a-1)1 -1 = 0
a -3a +3 -1 = 0
-2a +2 =0
-2a= -2
a = 1
Answered by
0
Answer:
1/2
Step-by-step explanation:
As 1 is the zero of the given polynomial, it means that it satisfies the given polynomial. So put 1 is the polynomial
1 = a(1)²-3(a-1)(1)-1
= a - 3a + 3 - 1
= 2-2a
Taking 2a on the other side and bringing 1 to the opposite side, we get
2a = 2-1 = 1
⇒a = 1/2
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