If one zero of the polynomial px =x2_6x+k is twice the other the find the value of k
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Let the roots of the equation x²-6x+q=0 be x and 2x.
⇒Sum of the roots x+2x=3x=-(-6)/1
⇒3x=6
⇒x=2.
⇒Product of the roots x(2x)=q/1
⇒2x²=q
⇒2(2²)=q
⇒q=8.
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