Question

If one zero of the polynomial q(x) = x2 + px + 8 is
double the other, then find the value of p and hence
both zeroes of q(x).​

Answer 1

Step-by-step explanation:

let zeros be x 2x

product of zeros=8/1=8

2x^2=8

x^2=4

x=2or -2

p=-sum of roots

p=-(2+4)=-6

or

p=-(-2-4)=6