Question

if one zero of the polynomial x^2-√3x+40 is 5 which is the other zero? ​

Answer 1

Step-by-step explanation:

x=5

x^2-√3x+40

=(5)²-5√3+40

=65-5√3

=5(13-√3)

The answer is not 0.

Therefore,the question is wrong.

Answer 2

Answer:

$One \: zero \: of \: the \: polynomial \\  \mathsf {x^{2}-13x+40}x2−13x+40 is \mathsf{5}5 . \\ </p><p>]</p><p>Let the other zero be p</p><p></p><p>Then we have two zeroes of the given polynomial as p and 5 .</p><p></p><p>Then we have two factor (X-5) and (X-P) of the given polynomial. Thus</p><p>[tex](x - 5) \: (x - p) = {x}^{2} - 13x + 40$

$= {x}^{2} - (p + 5)x + 5p = {x}^{2} - 13x + 40$

Now

Comparing among the Coefficient we get

• P+5=13
• 5p=40

We get p=8

The other zero is 8