If one zero of the polynomial x^2- 4x+ 1 is 2+ root 3, then find the other zero.
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Answer:
formula:
roots=-b+/-√b^2-4ac/2a
a=1,b=-4,c=1
substitution the values of a,b,c
-(-4)+/-√(-4)^2-4(1)(1)/2(1)
4+/-√16-4/2
4+/-√12/2
4+/-2√3/2
2(2+/-√3)/2
2+/-√3
2+√3 or 2-√3
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