if one zero of the polynomial x square - 4 x + 1 is 2 + root 3 write the other 0
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1
Answer:
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Answered by
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Answer:
2-√3
Step-by-step explanation:
usig x=(-b+-√D)/2a,
here D=b^2-4ac,
a=1,b=-4,c=1
x={-(-4)+-√(4^2-4*1*1)}/2(1),
x=(4+-√12)/2,
x=(4+-2√3)/2,
x=2+-√3,
therefore,
x=2+√3 & x=2-√3
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