if one zero of the polynomial x square - 4 x + K is 2 then find the value of k
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Quadratic Equation :- x²- 4x + k
NOTE :- Quadratic form always be like this : ax² + bx + c.
It is given that :- One zero of the polynomial = 2
Now, Substituting x in the equation. ( x = 2 )
p(x) = x²- 4x + k = 0
p(2) = 2² - 4(2) + k = 0
p(2) = 4 - 8 + k = 0
p(2) = - 4 + k = 0
∴ VALUE OF k = 4
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