If one zero of the polynomial( x square +9)x*x+13x+6a is reciprocal of other then find the value of a
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Hey !!
Let one zero be Alpha .
Other zero = 1/Alpha
P ( x ) = X² + 13X + 6a
Here,
a = 1 , b = 13 and C = 6a
Product of zeroes = C/A
Alpha × 1/Alpha = 6a / 1
1 = 6a
a = 1/6
Let one zero be Alpha .
Other zero = 1/Alpha
P ( x ) = X² + 13X + 6a
Here,
a = 1 , b = 13 and C = 6a
Product of zeroes = C/A
Alpha × 1/Alpha = 6a / 1
1 = 6a
a = 1/6
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