Question

if one zero of the polynomial x square minus kx + 1 is 1 then the value of k is​

Answer 1

Answer:

given :1 is zero of polynomial

f(x) =x^2-kx+1

put x=1

we get ,

=>1^2-k(1)+1=0

=>1+1-k=0

=>2-k=0

=>k=2

hope it helps you

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Answer 2

Explanation:

GIVEN:-)

→ One zeros of quadratic polynomial = -3.

→ Quadratic polynomial = ( k - 1 )x² + kx + 1.

Solution:-

→ P(x) = ( k -1 )x² + kx + 1 = 0.

→ p(-3) = ( k - 1 )(-3)² + k(-3) + 1 = 0.

=> ( k - 1 ) × 9 -3k + 1 = 0.

=> 9k - 9 -3k + 1 = 0.

=> 6k - 8 = 0.

=> 6k = 8.

$\large \boxed{=> k = \frac{8}{6} = \frac{4}{3} }$

Hence, the value of ‘k’ is founded .