Question

if one zero of the polynomial x squre -8x +(K+1) is double the other find the value of 'K' (how to solve this)​

Answer 1

Answer:

K = 119/9

Step-by-step explanation:

Let the one of the zero of the polynomial be A and so the other zero will be 2A

Sum of zeroes = -(Coefficient of x)/(Coefficient of x²)

A + 2A = -(-8)/1

3A = 8

A = 8/3

Product of zeroes = (Constant Term)/(Coefficient of x²)

A(2A) = (K + 1)/1

(8/3)(2*8/3) = K + 1

128/9 = K + 1

K = 128/9-1

K = 119/9

Hope it helps you

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