Math, asked by sahilray452, 1 month ago

If one zero of the polynomial x² - 12x + (3k-1) is five times the other then the value of k is : *

Answers

Answered by kartik597652
1

Let one zero of polynomial is t.

Then other zero will be 5t

The sum of two zeros of a polynomial = -b/a = 5/3

⇒t +5t=5/3

⇒6t=5/3

⇒t=5/18

⇒t=5/18 (1)

The multiplication of zeros = c/a = (2k+1)/3

5t×t=(2k+1)/3

5(5/18)^2 = (2k+1)/3

125/324=(2k+1)/3

125=108(2k+1)

125=216k +108

216k=17

k=17/216

Brainliest✌️ ✌️ ✌️

Answered by pulakmath007
0

SOLUTION

GIVEN

One zero of the polynomial x² - 12x + (3k-1) is five times the other

TO DETERMINE

The value of k

EVALUATION

Here the given Quadratic polynomial is

x² - 12x + (3k-1)

Comparing with the general quadratic polynomial ax² + bx + c we get a = 1 , b = - 12 , c = 3k - 1

Now it is given that one zero of the polynomial is five times the other

Let the zeroes are α and 5α

Sum of the zeroes = - b/a

⇒ α + 5α = 12/1

⇒ 6α = 12

⇒ α = 2

So the zeroes are 2 and 10

Now

Product of the zeroes = c/a

⇒ 2 × 10 = 3k - 1

⇒ 3k - 1 = 20

⇒ 3k = 21

⇒ k = 7

FINAL ANSWER

Hence the required value of k = 7

━━━━━━━━━━━━━━━━

Learn more from Brainly :-

1. find the equation that formed by increasing each root of 2x²-3x-1=0by 1

https://brainly.in/question/33063519

2. find the equation that formed by squaring each root of the equation x²+3x-2=0

https://brainly.in/question/33064705

Similar questions