Question

If one zero of the polynomial x2-√3x+40 is 5, what is the other zero ?​

Answer 1

Given data: ( question corrected )

One zero of the polynomial $\mathsf{x^{2}-13x+40}$ is $\mathsf{5}$.

To find:

The other zero

Step-by-step explanation:

Let the other zero be $\mathsf{p}$.

Then we have two zeroes of the given polynomial as $\mathsf{p}$ and $\mathsf{5}$.

Then we have two factors $\mathsf{(x-5)}$ and $\mathsf{(x-p)}$ of the given polynomial. Thus

$\quad \mathsf{(x-5)(x-p)=x^{2}-13x+40}$

$\Rightarrow \mathsf{x^{2}-(p+5)x+5p=x^{2}-13x+40}$

Now comparing among the coefficients, we get

• $\mathsf{p+5=13}$ and
• $\mathsf{5p=40}$

Solving, we get $\mathsf{p=8}$

Answer:

Therefore, the other zero is $\mathsf{8}$.

Answer 2

hope it helps you

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