if one zero of the polynomial x²+3x+k is reciprocal of the other find the value of k
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Let the given quadratic polynomial be p(x) = x2 + 3x + k Given one of the zero of the quadratic polynomial is 2. Hence p(2) = 0 Put x = 2 in p(x), we get p(2) = 22 + 3(2) + k ⇒ 0 = 4 + 6 + k ⇒ 0 = 10 + k ∴ k = – 10
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Answer:
k= 1
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