Question

if one zero of the polynomial x²-8x+k exceeds the other by 2 find the zeroes of the polynomial . also find the value of k . ​

Answer 1

Answer:

Here is your answer mate

Answer 2

Answer:

The value of K is 15 and other zeroes are 3,5.

Step-by-step explanation:

Polynomial is x ^ 2 - 8x + k

Therefore, a = 1 , b = - 8 , c = k

Let one of the zeroes be alpha

Therefore, other zero is alpha + 2 alpha + alpha + 2 = - b/a

Sum of zeroes

=> 2alpha + 2 = - - 8/1

=> 2alpha + 2 = 8

=> 2α = 6

=> alpha = 3

Therefore, one zero is 3

And other is 3 + 2 = 5

Also, Product of zeroes a x (alpha + 2) = c/a

=> 3 x 5 = k/1

=> k = 15