If one zero of the polynomial x2 +a is -3 then find its other zero.
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Answer:
Given x^2 + a has one of the zero as(-3)
=> (-3)^2. + a = 0
=> 9 + a= 0
=> a= -9
So the polynomial is x^2 - 9= (x-3)( x +3)
=> 3,-3 are the zeros
So the other zero of thebpolynomial is 3
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