Question

if one zero of the poynomial (a^2+9)x^2+3x+6a if reciprocal of the other, then find the value of a

Answer 1

let one zero be y
so other will be 1/y
y×1/y = 6/a^2+9
1=6/a^2+9
a^2+9=6
a^2= -3
a=√-3