Question

if one zero of the quadratic polynomia p(x)=4x2-8kx-9 is negative of the other then find the value of k?

Answer 1

Comparing f(x) = 4x2 - 8kx - 9  with ax2+bx+c we get
a=4; b=-8k and c=-9.

Since one root is the negative of the other, let us assume that the roots are p an -p.
Sum of the roots, a+(-a)=-b/a=-(-8k)/4
0=2k
k=0

Answer 2

Step-by-step explanation:

Answer :-

→ k = 0 .

Step-by-step explanation :- ------

It is given that,

→ One zeros of the given polynomial is negative of the other .

Let one zero of the given polynomial be x .

Then, the other zero is -x .

•°• Sum of zeros = x + ( - x ) = 0 .

But, Sum of zeros = -( coefficient of x )/( coefficient of x² ) = - ( -8k )/4 .

==> 2k = 0 .

==> k = 0/2 .

•°• k = 0 .

Hence, it is solved.