Question

if one zero of the quadratic polynomial 2x2 -3x + p is 3 finds its other zero value of p

Answer 1

q(x)=2x2-3x+p
q(3)=2×(3)^2-3×3+p
0 =2×9-9+p
0 =18-9+p
0 =9+p
p =-9

q(x)=2x2-3x+p
q(x)=2x2-3x-9
=2x2-(6-3)x-9
=2x2-6x+3x-9
=2x(x-3)+3(x-3)
=(2x+3)(x-3)
x=-3/2,3

Answer 2

Answer:

The other zero of the given polynomial is -3/2.

Step-by-step explanation:

Here, the given polynomial is,

$2x^2-3x+p$

Let, $f(x) = 2x^2-3x+p$

Given,

3 is a zero of f(x),

⇒ f(3) = 0

$\implies 2(3)^2-3(3)+p=0$

$\implies 18-9+p = 0\implies p = -9$

Thus, the polynomial will be,

$f(x) = 2x^2-3x-9$

$=2x^2-6x+3x-9=2x(x-3)+3(x-3)=(2x+3)(x-3)$

When f(x) = 0

(2x+3)(x-3) = 0 ⇒ 2x+3 = 0 ⇒ x =-3/2

Thus, the other zero of the given polynomial is -3/2.