Question

If one zero of the quadratic polynomial 4x^2-8kx+8x-9 is negative of the other, then find the zeroes of kx^2+3kx+2. Please ask for details if necessary(not by clicking the 'add your answer' button). Answer first and I'll mark your answer as The Brainliest.

Answer 1

Answer:

K = 1

X = -1 , -2

Step-by-step explanation:

Given,

4x^2-8kx+8x-9

also, one zero is negative of the other

so, one zero is '' -∝'' and the other is  ''∝''

we know the product of the zeoes is ''c/a''

[-∝] . ∝ = -9/4

-∝^2 = -9/4

∝^2 = 9/4

∝ = 3/2

one zreo is  -3/2 and the other is 3/2

4x^2-8kx+8x-9=0

4[3/2]^2-8k[3/2]+8[3/2]-9=0

9-12k+12-9=0

12=12k

k=1

∴⇒k = 1

kx^2+3kx+2 = 0

as k = 1

x^2+3x+2 = 0

x^2+x+2x+2 = 0

x[x+1]+2[x+1] = 0

[x+1][x+2] = 0

x=-1 , -2

∴ ⇒ X = -1 , -2