If one zero
of the quadratic polynomial,
4x² - 8kx - 9 is negative of the other
find k.
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Answer:
Let α and β be the zeros of the polynomial 4x²-8kx-9
It is given that α=-β
Then, α+β=0
-b/a=0
-(coefficient of x)/coefficient of x²=0
8k/4=0
2k=0
k=0
Step-by-step explanation:
Answer :-
→ k = 0 .
Step-by-step explanation :-
It is given that,
→ One zeros of the given polynomial is negative of the other .
Let one zero of the given polynomial be x .
Then, the other zero is -x .
•°• Sum of zeros = x + ( - x ) = 0 .
But, Sum of zeros = -( coefficient of x )/( coefficient of x² ) = - ( -8k )/4 .
==> 2k = 0 .
==> k = 0/2 .
•°• k = 0 .
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